SCALES
Procedure
Experiment 1- To construct a scale of 1:50 to read meters and decimeters and long enough to measure 9 m.
Lenght of the scale=R.F.×Maximum Length (Rounded of to next higher whole number) (If the maximum length is not known take length of the scale = 15cm to 30cm) Therefore, Length of the scale = (1/50)x(9x100)cm = 18cmCalculate length of the scale (l) using the formula-
- Draw a line AB of 18cm long and divide into 9 equal parts. Each representing 1m.
- Name the divisions. Place zero at the end of the first main unit.
- Subdivide the division to the left of zero into10 equal parts. (Each part represents 1decimeter).
- Always mention the R.F. or name of the scale.
Experiment 2- Construct a diagonal scale to measure 1/25th and 1/5th of a centimeter. Assume length of scale to be 15 cm.
- R.F. = 1/1
- Given, Length of the scale = 15cm.
- Draw a line of 15cm, and divide it into 15 equal parts. Each part represents 1cm.
- Divide the first division into 5 equal parts. Each represents 1/5th of 1 centimetre, which is equal to 0.2cm.
- By diagonal division, divide each such part 5 equal parts. Each part represents 1/25th of 1 centimetre, which is 0.04 centimetre.
- Always mention the R.F. or name of the scale.
Experiment 3- Construct a vernier scale of R.F. = 1/20 to read meters and decametres and centimetres, long enough to read upto 4 metres. Show a distance of 2.38 metres on the scale.
- Given, R.F. = 1/20 Lenght of the scale=R.F.× Maximum Length (Rounded of to next higher whole number) Therefore, Length of the scale = (1/20)x(4x100)cm = 20cm
- Draw a line of 20cm and divide it into 4 equal parts. Each part represents 1 meter.
- Divide the first part into 10 equal parts or divisions. Each division represents 10 cm. 10 cm = 0.1m = 1 m.s.d. (main scale division)
- Construct the forward reading vernier along with the main scale. Make the following calculations:
Least Count (LC) = 1 m.s.d. – 1 v.s.d.
1/10 m.s.d. = 1 m.s.d. – 1 v.s.d. or 1 v.s.d = 1 – (1/10) m.s.d. = 9/10 m.s.d or 10 v.s.d. = 9 m.s.d
- Starting at zero division mark at main scale, take a length of 9 m.s.d. and divide it into 10 equal parts.
- Each division represents 1 v.s.d. or 0.09 m or 9 cm.
- Make the following calculations: 1 v.s.d. = 0.09 m 2 v.s.d. = 2 x 0.09 m = 0.18 m
- Thus subtracting 0.18 m from 2.38 m (required distance), we get 2.2 m.
- This distance can be easily shown on the main scale.
- The sum of the distances from steps 8 and 9 is the required distance.