Convergence and computation time
Initial guess x 1 = 0 a n d x 2 = 1 \text{Initial guess} \quad x1 = 0 \quad and \quad x2 = 1 Initial guess x 1 = 0 an d x 2 = 1 x 3 = x 1 + x 2 2 x3 = \frac{x1 + x2}{2} x 3 = 2 x 1 + x 2 equation = e x p ( x ) × c o s ( x ) − 1.4 \text{equation } = exp(x) × cos(x) -1.4 equation = e x p ( x ) × cos ( x ) − 1.4 What is function value of 8th iteration using bisection method? \text{What is function value of 8th iteration using bisection method?} What is function value of 8th iteration using bisection method?
Explanation
Explanation
Explanation
Explanation
Initial guess x 1 = 0 a n d x 2 = 1 \text{Initial guess} \quad x1 = 0 \quad and \quad x2 = 1 Initial guess x 1 = 0 an d x 2 = 1 x 3 = x 1 + x 2 2 x3 = \frac{x1 + x2}{2} x 3 = 2 x 1 + x 2 equation = e x p ( x ) × c o s ( x ) − 1.4 \text{equation } = exp(x) × cos(x) -1.4 equation = e x p ( x ) × cos ( x ) − 1.4 What is root value of 8th iteration using bisection method? \text{What is root value of 8th iteration using bisection method?} What is root value of 8th iteration using bisection method?
Explanation
Explanation
Explanation
Explanation
Initial guess x 1 = 0 a n d x 2 = 1 \text{Initial guess} \quad x1 = 0 \quad and \quad x2 = 1 Initial guess x 1 = 0 an d x 2 = 1 x 3 = x 1 − f ( x 1 ) × ( ( x 2 − x 1 ) ( f ( x 2 ) − f ( x 1 ) ) ) x3 = x1 - f(x1) × \left(\frac{(x2 - x1)}{(f(x2) - f(x1))}\right) x 3 = x 1 − f ( x 1 ) × ( ( f ( x 2 ) − f ( x 1 )) ( x 2 − x 1 ) ) equation = c o s ( x ) − x × e x p ( x ) \text{equation } = cos(x)-x × exp(x) equation = cos ( x ) − x × e x p ( x ) What is function value of 6th iteration using false position method? \text{What is function value of 6th iteration using false position method?} What is function value of 6th iteration using false position method?
Explanation
Explanation
Explanation
Explanation
Initial guess x 1 = 0 a n d x 2 = 1 \text{Initial guess} \quad x1 = 0 \quad and \quad x2 = 1 Initial guess x 1 = 0 an d x 2 = 1 x 3 = x 1 − f ( x 1 ) × ( ( x 2 − x 1 ) ( f ( x 2 ) − f ( x 1 ) ) ) x3 = x1 - f(x1) × \left(\frac{(x2 - x1)}{(f(x2) - f(x1))}\right) x 3 = x 1 − f ( x 1 ) × ( ( f ( x 2 ) − f ( x 1 )) ( x 2 − x 1 ) ) equation = c o s ( x ) − x × e x p ( x ) \text{equation } = cos(x)-x × exp(x) equation = cos ( x ) − x × e x p ( x ) What is root value of 6th iteration using false position method? \text{What is root value of 6th iteration using false position method?} What is root value of 6th iteration using false position method?
Explanation
Explanation
Explanation
Explanation
Initial guess x 1 = 1 \text{Initial guess} \quad x1 = 1 Initial guess x 1 = 1 x 2 = x 1 − f ( x 1 ) d f ( x 1 ) x2 = x1 - \frac{f(x1)}{df(x1)} x 2 = x 1 − df ( x 1 ) f ( x 1 ) equation = x 2 − c o s ( x ) \text{equation } = x^2-cos(x) equation = x 2 − cos ( x ) d f ( x ) = 2 x + s i n ( x ) df(x) = 2x + sin(x) df ( x ) = 2 x + s in ( x ) What is function value of 3rd iteration using Newton Raphson method? \text{What is function value of 3rd iteration using Newton Raphson method?} What is function value of 3rd iteration using Newton Raphson method?
Explanation
Explanation
Explanation
Explanation
Initial guess x 1 = 1 \text{Initial guess} \quad x1 = 1 Initial guess x 1 = 1 x 2 = x 1 − f ( x 1 ) d f ( x 1 ) x2 = x1 - \frac{f(x1)}{df(x1)} x 2 = x 1 − df ( x 1 ) f ( x 1 ) equation = x 2 − c o s ( x ) \text{equation } = x^2-cos(x) equation = x 2 − cos ( x ) d f ( x ) = 2 x + s i n ( x ) df(x) = 2x + sin(x) df ( x ) = 2 x + s in ( x ) What is root value of 3rd iteration using Newton Raphson method? \text{What is root value of 3rd iteration using Newton Raphson method?} What is root value of 3rd iteration using Newton Raphson method?
Explanation
Explanation
Explanation
Explanation
Initial guess x 1 = 1 \text{Initial guess} \quad x1 = 1 Initial guess x 1 = 1 x 2 = g ( x 1 ) x2 = g(x1) x 2 = g ( x 1 ) equation = c o s ( x ) − x × e x p ( x ) \text{equation } = cos(x) - x × exp(x) equation = cos ( x ) − x × e x p ( x ) g ( x ) = c o s ( x ) e x p ( x ) g(x) = \frac{cos(x)}{exp(x)} g ( x ) = e x p ( x ) cos ( x ) What is function value of 6th iteration using one point iterative method? \text{What is function value of 6th iteration using one point iterative method?} What is function value of 6th iteration using one point iterative method?
Explanation
Explanation
Explanation
Explanation
Initial guess x 1 = 1 \text{Initial guess} \quad x1 = 1 Initial guess x 1 = 1 x 2 = g ( x 1 ) x2 = g(x1) x 2 = g ( x 1 ) equation = c o s ( x ) − x × e x p ( x ) \text{equation } = cos(x) - x × exp(x) equation = cos ( x ) − x × e x p ( x ) g ( x ) = c o s ( x ) e x p ( x ) g(x) = \frac{cos(x)}{exp(x)} g ( x ) = e x p ( x ) cos ( x ) What is root value of 6th iteration using one point iterative method? \text{What is root value of 6th iteration using one point iterative method?} What is root value of 6th iteration using one point iterative method?
Explanation
Explanation
Explanation
Explanation
Submit Quiz
