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Procedure
Simulation
Posttest
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Dynamics of Fluid Flow: Pitot Tube
Choose difficulty:
Beginner
Intermediate
Advanced
Discharge through orifice is given by
a:
C
d
a
0
a
1
2
g
h
a
1
2
−
a
2
2
\frac{C_d a_0 a_1 \sqrt{2gh}}{\sqrt{a_1^2 - a_2^2}}
a
1
2
−
a
2
2
C
d
a
0
a
1
2
g
h
Explanation
Explanation
b:
C
d
a
0
a
1
g
h
a
1
2
−
a
2
2
\frac{C_d a_0 a_1 \sqrt{gh}}{\sqrt{a_1^2 - a_2^2}}
a
1
2
−
a
2
2
C
d
a
0
a
1
g
h
Explanation
Explanation
c:
C
d
a
0
a
1
2
g
h
a
2
2
−
a
2
2
\frac{C_d a_0 a_1 \sqrt{2gh}}{\sqrt{a_2^2 - a_2^2}}
a
2
2
−
a
2
2
C
d
a
0
a
1
2
g
h
Explanation
Explanation
d:
C
d
a
0
a
1
2
g
h
a
2
2
\frac{C_d a_0 a_1 \sqrt{2gh}}{\sqrt{a_2^2}}
a
2
2
C
d
a
0
a
1
2
g
h
Explanation
Explanation
Velocity of flow by pitot tube is
a:
C
v
g
h
C_v \sqrt{gh}
C
v
g
h
Explanation
Explanation
b:
C
v
2
g
h
C_v 2gh
C
v
2
g
h
Explanation
Explanation
c:
C
v
2
g
h
C_v \sqrt{2gh}
C
v
2
g
h
Explanation
Explanation
d:
2
g
h
\sqrt{2gh}
2
g
h
Explanation
Explanation
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