Elliptical equation-possion equation

2Tx2+2Ty2=8(x2+y2+10)=f(x,y) \frac{\partial^2 T}{\partial x^2} + \frac{\partial^2 T}{\partial y^2} = 8(x^2+y^2+10) = f(x, y) Find the value of T1. Boundry conditions are given as:
The temperature of all four surfaces are 0oC.
Given that,
l=3, w=3. Take h=1 and k=1.
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2Tx2+2Ty2=11(x2+y2+10)=f(x,y) \frac{\partial^2 T}{\partial x^2} + \frac{\partial^2 T}{\partial y^2} = -11(x^2+y^2+10) = f(x, y) Find the value of T1. Boundry conditions are given as:
The temperature of all four surfaces are 0oC.
Given that,
l=3, w=3. Take h=1 and k=1.
Explanation

Explanation

Explanation

Explanation

Explanation

Explanation

Explanation

Explanation