Rate constant and activation energy of potassium permanganate and oxalic acid reaction

Materials & Reagents Required:

  1. Temperature controlled water bath.
  2. Volumetric flask (250 ml)
  3. Conical flask (250 ml)
  4. Test tubes
  5. Micropipette (5 ml)

Procedure in laboratory (diagram)







Procedure in laboratory


Data and the analysis:
After mixing 20 mL, 0.5(M) oxalic acid with 0.02(M) KMnO4,
The Concentration of KMnO4 becomes = 0.0067 (M)
The Concentration of Oxalic acid becomes = 0.33 (M)

We have calculated the rate by using following equation
Rate= [KMnO4]/time

Next, we have measured rate constant (k) by using following equation
k = rate / [KMnO4] [Oxalic Acid]




Therefore, Slope = -Ea/R = - 8270 K Then Ea E(a )=(8270 K ×R) =(8270 K×8.314 J 〖mol〗-1 K-1 ) = 68.75 kJ 〖mol〗-1
Activation Energy for this chemical reaction = 68.75 kJ mol-1
Analysis
Therefore,
Slope = -Ea/R = - 8270 K
Then Ea Ea =(8270 K ×R)
=(8270 K×8.314 J 〖mol〗-1 K-1 )
= 68.75 KJ 〖mol〗^(-1)