Forging Hammer as 2DOF system - Impulse Excitation
Impulse force can be defined as a force of large magnitude that acts for a short time. It can be measured by finding the change it causes in the momentum of system.
Impulse=FΔT=mx˙2−mx˙1
The initial conditions are given by
x(t=0)=x0=0
x˙(t=0)=x˙0=m1
Forging is a manufacturing process which involves shaping metals using localized compressive forces i.e., blows are delivered by hammers on the billet.
The governing differential equation are,
m1x¨1(t)+(k1+k2)x1(t)−k2x2(t)=0
m2x¨2(t)−k2x1(t)+k2x2(t)=0
Writing in matrix form,
[m100m2]{x¨1(t)x¨2(t)}+[k1+k2−k2−k2k2]{x1(t)x2(t)}={00}
Where,
x1(t)=X1cos(ωt+ϕ)
x2(t)=X2cos(ωt+ϕ)
Substituting this and writing in the matrix form,
[−m1ω2+k1+k2−k2−k2−m2ω2+k2]{X1X2}={00}
To obtain the solution the determminant of the coefficient of X1 and X2 must be zero,
(m1m2)ω4−{(k1+k2)m2+k2m1}ω2+(k1+k2)k2−k22=0
where, ω1 and ω2 are roots of the equations,
ω12,ω22=21{m1m2(k1+k2)m2+k2m1}∓21{(m1m2(k1+k2)m2+k2m1)2−4m1m2(k1+k2)k2−k22}1/2
The mode shape,
For the first mode X1={X1(1)X2(1)}=X1(1){1r1}where r1=X1(1)X2(1)
Fot the second mode X2={X1(2)X2(2)}=X1(2){1r2}where r2=X1(2)X2(2)
The general form of equation of motion of m1 and m2 are,
x1=X1(1)cos(ω1t+ϕ1)+X1(2)cos(ω2t+ϕ2)
x2=r1X1(1)cos(ω1t+ϕ1)+r2X1(2)cos(ω2t+ϕ2)
The initial conditions (at t=0) are,
x1=0x˙1=0
x2=0x˙2=0
Based on the initial conditions, X1(1), X1(2), ϕ1 and ϕ2 can be obtained.