Find the mean temperature from a cubical furnace kept on a concrete floor. If the outside temperature of the furnace is 80^oC and surrounding air is at 20^oC. The sides of the furnace are 1m. At mean temperature, take the following properties.
ρ = 1.0193
K = 0.0283w/m-k
C_P = 1005 J/Kg-k
P_r = 0.698
μ = 19.6*10^-6 Ns/m
ν = 17.95*10^-6 m²/s
$$T_m = \frac{T_s + T_f}{2}$$

Find the rate of heat loss from a cubical furnace kept on a concrete floor. If the outside temperature of the furnace is 80^oC and surrounding air is at 20^oC. The sides of the furnace are 1m. At mean temperature, take the following properties.
ρ = 1.0193
K = 0.0283w/m-k
C_P = 1005 J/Kg-k
P_r = 0.698
μ = 19.6*10^-6 Ns/m
ν = 17.95*10^-6 m²/s
Q = Q_T + Q_S