Objective:

This experiment aims to carry out simplified load calculation and structural analysis of a 3D frame structure by breaking down into 2D frames. It deals with computation of dead loads (slabs and finish, beam and columns), imposed (live) loads & earthquake loads.

Step-1: (a) Click on Bring button to bring the 3D frame . Step-1: (b) Click on split button to show the split of the first 2D frame. Step-1: (c) Click on split 2 button to show the split of the second 2D frame.

Calculations for Slab S-1

Dead Load of the slab = thickness x 25 = 0.15 x 25 = 3.75kN/m²
Dead load on 50mm (thickness) floor finish = 0.05 x unit weight of PCC = 0.05 x 24 = 0.36 kN/m²

1. Total Dead Load Intensity

[      +      ] =

Solve

2. Now load of trapezoidal portion of the slab (APQB) acting on beam B₁

Area of the trapezoidal portion x Total DL intensity

[      x      ] =

Solve

Similarly DL of slab DPQC acting on Beam B₃ = 21.75 kN

3. Now load of triangular portion of the slab (BQC) acting on beam B₂

Area of the triangular portion x Total DL intensity

[      x      ] =

Solve

Similarly DL of slab (BQD) acting on Beam B₄ = 9.24 kN
Total Dead load of the slab = 61.62
Now, Imposed Load = 3kN/m²
Therefore, the imposed load transfered to the beams

B₁ =        B₂ =        B₃ =        B₄ =       

Check

Also, Total IL (Live load) of slab =

Calculation of self weight of beam

Self weight of beam B₁ = Volume (L₁ x Width x Thickness) x Density of concrete.

[      x      x      ] x 25 =

Solve

Similarly the self weight of beam B₃ =

Self weight of Beam B₂ = Volume (L₂ x Width x Thickness) x Density of concrete.

[      x      x      ] x 25 =

Calc.

Similarly the self weight of beam B₄ =

Now, Total DL of the Slab + Beams (B₁, B₂, B₃, B₄) = 97.63 kN

Calculation of self weight of columns

Self weight of the column C₁ = Volume (l_c x width x thickness) x 25.

[ 3.5 x 0.4 x 0.4 ] x 25 = 14kN

Similarly the self weight of column C₂ = C₃ = C₄ = 14 kN. ]

Now Calculate the total load transfered to the footing of each column

$$ = \left(\frac{1}{4} \text{ total weight of slab}\right) + \frac{\text{self weight of beam B1 + B2}}{2} + \text{C1}$$

Total imposed load (IL) on footing = 1/4 of IL on slab = 45/ 4 = 11.25 kN

Seismic Load Analysis

Horizontal seismic cofficient (A_H) =

select Structure 1 select seismic zone 0.10 for Zone 1 (low) 0.16 for Zone 2 (moderate) 0.24 for Zone 3 (severe) 0.36 for Zone 4 (very severe) Importance Factor other Buildings (1.2) Important Buildings (1.5) select type of frame Ordinary MR Frames (3.0) Special MR Frames (5.0) Steel MR Frames (5.0)

Calculate A_h =

Base Shear(F) = A_h x (total structure load) Base Shear =

$$W = {4} { x (}\text{ Total weight of slab} + \frac{\text{self weight of beam B1 + B2}}{2} + \text{C1) + {25% of total Iimposed Load (IL)}}$$

Calculate