SOLVE - heat transfer - Heat transfer by Natural Convection

To calculate heat transfer coefficient and heat transfer rate from vertical cylinder in natural convection.

Diameter, d = 44mm

Length t = 500mm

Voltage

10.81

T₁ (°C) 10

T₂ (°C) 10

T₃ (°C) 10

T₄ (°C) 10

T₅ (°C) 10

T₆ (°C) 10

T₇ (°C) 10

T₈ (°C) 10

Temperature Gradient

Please enter a value rounded upto two decimal points

Volumetric coefficient

β = ¹⁄_Tm

β =

1/K

Grashof number

Gr = ^{L³.β.g.(Ts - Ta)}⁄ _{γ ²}

γ = 1.846*10 ^-5

Gr =

Nusselt Number,

Nu = 0.53(Ra) ^1/4 if Ra < 10 ⁵
0.56(Ra) ^1/4 if 10 ⁵ < Ra < 10 ⁸
0.13(Ra) ^1/3 if 10 ⁸ < Ra < 10 ¹²

Ra = Gr.Pr .... Pr = 0.697

Nu =

heat transfer coefficient,

h = ^Nu.k⁄ _L

k = 0.02861

h =

W/m² K

Heat transfer rate

Qc = h.A.(Ts - Ta)

A = π.Ds.L

Qc =

W

Heat transfer by Natural Convection