Izod Impact Test
Objective:
To find the impact resistance of mild steel and cast iron.
Apparatus used:
Impact Testing Machine
Select the Izod test specimen.
Selected specimen :
Cast Iron
Mild Steel
Cast Iron
Mild Steel
| Length L (mm) | |
| Breadth B (mm) | |
| Depth D (mm) | |
| Depth of Notch-d (mm) |
| Length L (mm) | |
| Breadth B (mm) | |
| Depth D (mm) | |
| Depth of Notch-d (mm) |
Test for friction loss is conducted by adjusting the pointer to 164 Joules, then the pendulum is released by operating the lever without keeping the specimen.
Loss of energy due to friction Ef=_____J
The Izod test specimen as per Indian Standards IS:3766-1977 is placed in position.
Selected specimen :
Cast Iron
Mild Steel
| Length L (mm) | |
| Breadth B (mm) | |
| Depth D (mm) | |
| Depth of Notch-d (mm) |
| Length L (mm) | |
| Breadth B (mm) | |
| Depth D (mm) | |
| Depth of Notch-d (mm) |
The pendulum is released. The hammer strikes against the specimen, breaks it and swings further then the observation is noted down.
Observations:
Initial energy of the hammer = 164 J
Loss of energy due to friction, Ef =
Total Loss of energy Et during transit of hammer =
Energy for failure of specimen= KU / Impact Value = Et - Ef =
Initial energy of the hammer = 164 J
Loss of energy due to friction, Ef =
Total Loss of energy Et during transit of hammer =
Energy for failure of specimen= KU / Impact Value = Et - Ef =
| Trial | Loss of energy due to friction, Ef (J) | Total Loss of energy Et during transit of hammer (J) | Energy for failure of specimen = KU / Impact Value = Et - Ef (J) |
| 1 | |||
| 2 | |||
| 3 |
Average energy for failure of specimen =
Trial =
